0=-0.6x^2-0.2x+300

Solution for 0=-0.6x^2-0.2x+300 equation:

0=-0.6x^2-0.2x+300

We move all terms to the left:

0-(-0.6x^2-0.2x+300)=0

We add all the numbers together, and all the variables

-(-0.6x^2-0.2x+300)=0

We get rid of parentheses

0.6x^2+0.2x-300=0

a = 0.6; b = 0.2; c = -300;
Δ = b2-4ac
Δ = 0.22-4·0.6·(-300)
Δ = 720.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.2)-\sqrt{720.04}}{2*0.6}=\frac{-0.2-\sqrt{720.04}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.2)+\sqrt{720.04}}{2*0.6}=\frac{-0.2+\sqrt{720.04}}{1.2}
$